3x*2x-6x+(3x-8x+5x)=0

Solution for 3x*2x-6x+(3x-8x+5x)=0 equation:

3x*2x-6x+(3x-8x+5x)=0

We add all the numbers together, and all the variables

3x*2x-6x+0=0

We add all the numbers together, and all the variables

-6x+3x*2x=0

Wy multiply elements

6x^2-6x=0

a = 6; b = -6; c = 0;
Δ = b2-4ac
Δ = -62-4·6·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-6}{2*6}=\frac{0}{12}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+6}{2*6}=\frac{12}{12}
=1
$