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3x*2x=2133333
We move all terms to the left:
3x*2x-(2133333)=0
Wy multiply elements
6x^2-2133333=0
a = 6; b = 0; c = -2133333;
Δ = b2-4ac
Δ = 02-4·6·(-2133333)
Δ = 51199992
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{51199992}=\sqrt{36*1422222}=\sqrt{36}*\sqrt{1422222}=6\sqrt{1422222}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{1422222}}{2*6}=\frac{0-6\sqrt{1422222}}{12} =-\frac{6\sqrt{1422222}}{12} =-\frac{\sqrt{1422222}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{1422222}}{2*6}=\frac{0+6\sqrt{1422222}}{12} =\frac{6\sqrt{1422222}}{12} =\frac{\sqrt{1422222}}{2} $
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