3x*2x=4800

Solution for 3x*2x=4800 equation:

3x*2x=4800

We move all terms to the left:

3x*2x-(4800)=0

Wy multiply elements

6x^2-4800=0

a = 6; b = 0; c = -4800;
Δ = b2-4ac
Δ = 02-4·6·(-4800)
Δ = 115200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{115200}=\sqrt{57600*2}=\sqrt{57600}*\sqrt{2}=240\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-240\sqrt{2}}{2*6}=\frac{0-240\sqrt{2}}{12}
=-\frac{240\sqrt{2}}{12}
=-20\sqrt{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+240\sqrt{2}}{2*6}=\frac{0+240\sqrt{2}}{12}
=\frac{240\sqrt{2}}{12}
=20\sqrt{2}
$