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3x*2x=75
We move all terms to the left:
3x*2x-(75)=0
Wy multiply elements
6x^2-75=0
a = 6; b = 0; c = -75;
Δ = b2-4ac
Δ = 02-4·6·(-75)
Δ = 1800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1800}=\sqrt{900*2}=\sqrt{900}*\sqrt{2}=30\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-30\sqrt{2}}{2*6}=\frac{0-30\sqrt{2}}{12} =-\frac{30\sqrt{2}}{12} =-\frac{5\sqrt{2}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+30\sqrt{2}}{2*6}=\frac{0+30\sqrt{2}}{12} =\frac{30\sqrt{2}}{12} =\frac{5\sqrt{2}}{2} $
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