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3x*3x+7=55
We move all terms to the left:
3x*3x+7-(55)=0
We add all the numbers together, and all the variables
3x*3x-48=0
Wy multiply elements
9x^2-48=0
a = 9; b = 0; c = -48;
Δ = b2-4ac
Δ = 02-4·9·(-48)
Δ = 1728
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1728}=\sqrt{576*3}=\sqrt{576}*\sqrt{3}=24\sqrt{3}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-24\sqrt{3}}{2*9}=\frac{0-24\sqrt{3}}{18} =-\frac{24\sqrt{3}}{18} =-\frac{4\sqrt{3}}{3} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+24\sqrt{3}}{2*9}=\frac{0+24\sqrt{3}}{18} =\frac{24\sqrt{3}}{18} =\frac{4\sqrt{3}}{3} $
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