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3x*3x-2x=6x+12-8x
We move all terms to the left:
3x*3x-2x-(6x+12-8x)=0
We add all the numbers together, and all the variables
3x*3x-2x-(-2x+12)=0
We add all the numbers together, and all the variables
-2x+3x*3x-(-2x+12)=0
Wy multiply elements
9x^2-2x-(-2x+12)=0
We get rid of parentheses
9x^2-2x+2x-12=0
We add all the numbers together, and all the variables
9x^2-12=0
a = 9; b = 0; c = -12;
Δ = b2-4ac
Δ = 02-4·9·(-12)
Δ = 432
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{432}=\sqrt{144*3}=\sqrt{144}*\sqrt{3}=12\sqrt{3}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{3}}{2*9}=\frac{0-12\sqrt{3}}{18} =-\frac{12\sqrt{3}}{18} =-\frac{2\sqrt{3}}{3} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{3}}{2*9}=\frac{0+12\sqrt{3}}{18} =\frac{12\sqrt{3}}{18} =\frac{2\sqrt{3}}{3} $
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