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3x*3x-34x-24=0
We add all the numbers together, and all the variables
-34x+3x*3x-24=0
Wy multiply elements
9x^2-34x-24=0
a = 9; b = -34; c = -24;
Δ = b2-4ac
Δ = -342-4·9·(-24)
Δ = 2020
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2020}=\sqrt{4*505}=\sqrt{4}*\sqrt{505}=2\sqrt{505}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-34)-2\sqrt{505}}{2*9}=\frac{34-2\sqrt{505}}{18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-34)+2\sqrt{505}}{2*9}=\frac{34+2\sqrt{505}}{18} $
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