3x*3x-50=2x*2x+75

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Solution for 3x*3x-50=2x*2x+75 equation:



3x*3x-50=2x*2x+75
We move all terms to the left:
3x*3x-50-(2x*2x+75)=0
Wy multiply elements
9x^2-(2x*2x+75)-50=0
We get rid of parentheses
9x^2-2x*2x-75-50=0
We add all the numbers together, and all the variables
9x^2-2x*2x-125=0
Wy multiply elements
9x^2-4x^2-125=0
We add all the numbers together, and all the variables
5x^2-125=0
a = 5; b = 0; c = -125;
Δ = b2-4ac
Δ = 02-4·5·(-125)
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2500}=50$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-50}{2*5}=\frac{-50}{10} =-5 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+50}{2*5}=\frac{50}{10} =5 $

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