3x*4x+4=16

Solution for 3x*4x+4=16 equation:

3x*4x+4=16

We move all terms to the left:

3x*4x+4-(16)=0

We add all the numbers together, and all the variables

3x*4x-12=0

Wy multiply elements

12x^2-12=0

a = 12; b = 0; c = -12;
Δ = b2-4ac
Δ = 02-4·12·(-12)
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-24}{2*12}=\frac{-24}{24}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+24}{2*12}=\frac{24}{24}
=1
$