3x*4x=34

Solution for 3x*4x=34 equation:

3x*4x=34

We move all terms to the left:

3x*4x-(34)=0

Wy multiply elements

12x^2-34=0

a = 12; b = 0; c = -34;
Δ = b2-4ac
Δ = 02-4·12·(-34)
Δ = 1632
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1632}=\sqrt{16*102}=\sqrt{16}*\sqrt{102}=4\sqrt{102}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{102}}{2*12}=\frac{0-4\sqrt{102}}{24}
=-\frac{4\sqrt{102}}{24}
=-\frac{\sqrt{102}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{102}}{2*12}=\frac{0+4\sqrt{102}}{24}
=\frac{4\sqrt{102}}{24}
=\frac{\sqrt{102}}{6}
$