3x*4x=3840

Solution for 3x*4x=3840 equation:

3x*4x=3840

We move all terms to the left:

3x*4x-(3840)=0

Wy multiply elements

12x^2-3840=0

a = 12; b = 0; c = -3840;
Δ = b2-4ac
Δ = 02-4·12·(-3840)
Δ = 184320
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{184320}=\sqrt{36864*5}=\sqrt{36864}*\sqrt{5}=192\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-192\sqrt{5}}{2*12}=\frac{0-192\sqrt{5}}{24}
=-\frac{192\sqrt{5}}{24}
=-8\sqrt{5}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+192\sqrt{5}}{2*12}=\frac{0+192\sqrt{5}}{24}
=\frac{192\sqrt{5}}{24}
=8\sqrt{5}
$