3x*4x=42

Solution for 3x*4x=42 equation:

3x*4x=42

We move all terms to the left:

3x*4x-(42)=0

Wy multiply elements

12x^2-42=0

a = 12; b = 0; c = -42;
Δ = b2-4ac
Δ = 02-4·12·(-42)
Δ = 2016
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2016}=\sqrt{144*14}=\sqrt{144}*\sqrt{14}=12\sqrt{14}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{14}}{2*12}=\frac{0-12\sqrt{14}}{24}
=-\frac{12\sqrt{14}}{24}
=-\frac{\sqrt{14}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{14}}{2*12}=\frac{0+12\sqrt{14}}{24}
=\frac{12\sqrt{14}}{24}
=\frac{\sqrt{14}}{2}
$