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3x*4x=480000
We move all terms to the left:
3x*4x-(480000)=0
Wy multiply elements
12x^2-480000=0
a = 12; b = 0; c = -480000;
Δ = b2-4ac
Δ = 02-4·12·(-480000)
Δ = 23040000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{23040000}=4800$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4800}{2*12}=\frac{-4800}{24} =-200 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4800}{2*12}=\frac{4800}{24} =200 $
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