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3x*x+5x=42
We move all terms to the left:
3x*x+5x-(42)=0
We add all the numbers together, and all the variables
5x+3x*x-42=0
Wy multiply elements
3x^2+5x-42=0
a = 3; b = 5; c = -42;
Δ = b2-4ac
Δ = 52-4·3·(-42)
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{529}=23$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-23}{2*3}=\frac{-28}{6} =-4+2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+23}{2*3}=\frac{18}{6} =3 $
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