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3x*x-13x-10=0
We add all the numbers together, and all the variables
-13x+3x*x-10=0
Wy multiply elements
3x^2-13x-10=0
a = 3; b = -13; c = -10;
Δ = b2-4ac
Δ = -132-4·3·(-10)
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{289}=17$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-17}{2*3}=\frac{-4}{6} =-2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+17}{2*3}=\frac{30}{6} =5 $
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