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3x*x-5x+2=0
We add all the numbers together, and all the variables
-5x+3x*x+2=0
Wy multiply elements
3x^2-5x+2=0
a = 3; b = -5; c = +2;
Δ = b2-4ac
Δ = -52-4·3·2
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-1}{2*3}=\frac{4}{6} =2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+1}{2*3}=\frac{6}{6} =1 $
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