3x*x=435

Solution for 3x*x=435 equation:

3x*x=435

We move all terms to the left:

3x*x-(435)=0

Wy multiply elements

3x^2-435=0

a = 3; b = 0; c = -435;
Δ = b2-4ac
Δ = 02-4·3·(-435)
Δ = 5220
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5220}=\sqrt{36*145}=\sqrt{36}*\sqrt{145}=6\sqrt{145}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{145}}{2*3}=\frac{0-6\sqrt{145}}{6}
=-\frac{6\sqrt{145}}{6}
=-\sqrt{145}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{145}}{2*3}=\frac{0+6\sqrt{145}}{6}
=\frac{6\sqrt{145}}{6}
=\sqrt{145}
$