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3x*x=448
We move all terms to the left:
3x*x-(448)=0
Wy multiply elements
3x^2-448=0
a = 3; b = 0; c = -448;
Δ = b2-4ac
Δ = 02-4·3·(-448)
Δ = 5376
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{5376}=\sqrt{256*21}=\sqrt{256}*\sqrt{21}=16\sqrt{21}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16\sqrt{21}}{2*3}=\frac{0-16\sqrt{21}}{6} =-\frac{16\sqrt{21}}{6} =-\frac{8\sqrt{21}}{3} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16\sqrt{21}}{2*3}=\frac{0+16\sqrt{21}}{6} =\frac{16\sqrt{21}}{6} =\frac{8\sqrt{21}}{3} $
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