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3x+((70-35x)/3)=20
We move all terms to the left:
3x+((70-35x)/3)-(20)=0
We add all the numbers together, and all the variables
3x+((-35x+70)/3)-20=0
We multiply all the terms by the denominator
3x*3)+((-35x+70)-20*3)=0
We add all the numbers together, and all the variables
3x*3)+((-35x+70)=0
Wy multiply elements
9x^2=0
a = 9; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·9·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{18}=0$
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