3x+(-3)=4(x-2)

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Solution for 3x+(-3)=4(x-2) equation:



3x+(-3)=4(x-2)
We move all terms to the left:
3x+(-3)-(4(x-2))=0
We add all the numbers together, and all the variables
3x-(4(x-2))-3=0
We calculate terms in parentheses: -(4(x-2)), so:
4(x-2)
We multiply parentheses
4x-8
Back to the equation:
-(4x-8)
We get rid of parentheses
3x-4x+8-3=0
We add all the numbers together, and all the variables
-1x+5=0
We move all terms containing x to the left, all other terms to the right
-x=-5
x=-5/-1
x=+5

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