3x+(-40)=2

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Solution for 3x+(-40)=2 equation: 



3x+(-40)=2

We move all terms to the left:

3x+(-40)-(2)=0

determiningTheFunctionDomain
3x-2+(-40)=0

We add all the numbers together, and all the variables

3x-42=0

We move all terms containing x to the left, all other terms to the right

3x=42

x=42/3

x=14

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