3x+(-5)=-40x+(-48)

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Solution for 3x+(-5)=-40x+(-48) equation: 



3x+(-5)=-40x+(-48)

We move all terms to the left:

3x+(-5)-(-40x+(-48))=0

We add all the numbers together, and all the variables

3x-(-40x+(-48))-5=0



We calculate terms in parentheses: -(-40x+(-48)), so:

-40x+(-48)

We add all the numbers together, and all the variables

-40x-48

Back to the equation:

-(-40x-48)



We get rid of parentheses

3x+40x+48-5=0

We add all the numbers together, and all the variables

43x+43=0

We move all terms containing x to the left, all other terms to the right

43x=-43

x=-43/43

x=-1

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