3x+(-5-(x+3))=8x+(-5x-9)

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Solution for 3x+(-5-(x+3))=8x+(-5x-9) equation: 



3x+(-5-(x+3))=8x+(-5x-9)

We move all terms to the left:

3x+(-5-(x+3))-(8x+(-5x-9))=0



We calculate terms in parentheses: +(-5-(x+3)), so:

-5-(x+3)

determiningTheFunctionDomain
-(x+3)-5

We get rid of parentheses

-x-3-5

We add all the numbers together, and all the variables

-1x-8

Back to the equation:

+(-1x-8)





We calculate terms in parentheses: -(8x+(-5x-9)), so:

8x+(-5x-9)

We get rid of parentheses

8x-5x-9

We add all the numbers together, and all the variables

3x-9

Back to the equation:

-(3x-9)



We get rid of parentheses

3x-1x-3x-8+9=0

We add all the numbers together, and all the variables

-1x+1=0

We move all terms containing x to the left, all other terms to the right

-x=-1

x=-1/-1

x=1

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