3x+(-x-4)=8

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Solution for 3x+(-x-4)=8 equation:



3x+(-x-4)=8
We move all terms to the left:
3x+(-x-4)-(8)=0
We add all the numbers together, and all the variables
3x+(-1x-4)-8=0
We get rid of parentheses
3x-1x-4-8=0
We add all the numbers together, and all the variables
2x-12=0
We move all terms containing x to the left, all other terms to the right
2x=12
x=12/2
x=6

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