3x+(1/4)x=26

Solution for 3x+(1/4)x=26 equation:

3x+(1/4)x=26

We move all terms to the left:

3x+(1/4)x-(26)=0


Domain of the equation: 4)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

3x+(+1/4)x-26=0

We multiply parentheses

x^2+3x-26=0

a = 1; b = 3; c = -26;
Δ = b2-4ac
Δ = 32-4·1·(-26)
Δ = 113
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{113}}{2*1}=\frac{-3-\sqrt{113}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{113}}{2*1}=\frac{-3+\sqrt{113}}{2}
$