3x+(1/4x)=26

Solution for 3x+(1/4x)=26 equation:

3x+(1/4x)=26

We move all terms to the left:

3x+(1/4x)-(26)=0


Domain of the equation: 4x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

3x+(+1/4x)-26=0

We get rid of parentheses

3x+1/4x-26=0

We multiply all the terms by the denominator


3x*4x-26*4x+1=0

Wy multiply elements

12x^2-104x+1=0

a = 12; b = -104; c = +1;
Δ = b2-4ac
Δ = -1042-4·12·1
Δ = 10768
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{10768}=\sqrt{16*673}=\sqrt{16}*\sqrt{673}=4\sqrt{673}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-104)-4\sqrt{673}}{2*12}=\frac{104-4\sqrt{673}}{24}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-104)+4\sqrt{673}}{2*12}=\frac{104+4\sqrt{673}}{24}
$