3x+(10-x)=20

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Solution for 3x+(10-x)=20 equation: 



3x+(10-x)=20

We move all terms to the left:

3x+(10-x)-(20)=0

We add all the numbers together, and all the variables

3x+(-1x+10)-20=0

We get rid of parentheses

3x-1x+10-20=0

We add all the numbers together, and all the variables

2x-10=0

We move all terms containing x to the left, all other terms to the right

2x=10

x=10/2

x=5

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