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3x+(12/5)=49
We move all terms to the left:
3x+(12/5)-(49)=0
determiningTheFunctionDomain 3x-49+(12/5)=0
We add all the numbers together, and all the variables
3x-49+(+12/5)=0
We get rid of parentheses
3x-49+12/5=0
We multiply all the terms by the denominator
3x*5+12-49*5=0
We add all the numbers together, and all the variables
3x*5-233=0
Wy multiply elements
15x-233=0
We move all terms containing x to the left, all other terms to the right
15x=233
x=233/15
x=15+8/15
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