3x+(12x+1)+(16x-7)=180

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Solution for 3x+(12x+1)+(16x-7)=180 equation: 



3x+(12x+1)+(16x-7)=180

We move all terms to the left:

3x+(12x+1)+(16x-7)-(180)=0

We get rid of parentheses

3x+12x+16x+1-7-180=0

We add all the numbers together, and all the variables

31x-186=0

We move all terms containing x to the left, all other terms to the right

31x=186

x=186/31

x=6

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