3x+(18-x)/2=39

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Solution for 3x+(18-x)/2=39 equation:



3x+(18-x)/2=39
We move all terms to the left:
3x+(18-x)/2-(39)=0
We add all the numbers together, and all the variables
3x+(-1x+18)/2-39=0
We multiply all the terms by the denominator
3x*2+(-1x+18)-39*2=0
We add all the numbers together, and all the variables
3x*2+(-1x+18)-78=0
Wy multiply elements
6x+(-1x+18)-78=0
We get rid of parentheses
6x-1x+18-78=0
We add all the numbers together, and all the variables
5x-60=0
We move all terms containing x to the left, all other terms to the right
5x=60
x=60/5
x=12

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