3x+(2-4x);x=4

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Solution for 3x+(2-4x);x=4 equation:



3x+(2-4x)x=4
We move all terms to the left:
3x+(2-4x)x-(4)=0
We add all the numbers together, and all the variables
3x+(-4x+2)x-4=0
We multiply parentheses
-4x^2+3x+2x-4=0
We add all the numbers together, and all the variables
-4x^2+5x-4=0
a = -4; b = 5; c = -4;
Δ = b2-4ac
Δ = 52-4·(-4)·(-4)
Δ = -39
Delta is less than zero, so there is no solution for the equation

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