3x+(2/3)x=49

Solution for 3x+(2/3)x=49 equation:

3x+(2/3)x=49

We move all terms to the left:

3x+(2/3)x-(49)=0


Domain of the equation: 3)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

3x+(+2/3)x-49=0

We multiply parentheses

2x^2+3x-49=0

a = 2; b = 3; c = -49;
Δ = b2-4ac
Δ = 32-4·2·(-49)
Δ = 401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{401}}{2*2}=\frac{-3-\sqrt{401}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{401}}{2*2}=\frac{-3+\sqrt{401}}{4}
$