3x+(2/3)x=98

Solution for 3x+(2/3)x=98 equation:

3x+(2/3)x=98

We move all terms to the left:

3x+(2/3)x-(98)=0


Domain of the equation: 3)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

3x+(+2/3)x-98=0

We multiply parentheses

2x^2+3x-98=0

a = 2; b = 3; c = -98;
Δ = b2-4ac
Δ = 32-4·2·(-98)
Δ = 793
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{793}}{2*2}=\frac{-3-\sqrt{793}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{793}}{2*2}=\frac{-3+\sqrt{793}}{4}
$