3x+(2x+1)+(2(x+4))=37

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Solution for 3x+(2x+1)+(2(x+4))=37 equation: 


Simplifying
3x + (2x + 1) + (2(x + 4)) = 37

Reorder the terms:
3x + (1 + 2x) + (2(x + 4)) = 37

Remove parenthesis around (1 + 2x)
3x + 1 + 2x + (2(x + 4)) = 37

Reorder the terms:
3x + 1 + 2x + (2(4 + x)) = 37
3x + 1 + 2x + ((4 * 2 + x * 2)) = 37
3x + 1 + 2x + ((8 + 2x)) = 37
3x + 1 + 2x + (8 + 2x) = 37

Remove parenthesis around (8 + 2x)
3x + 1 + 2x + 8 + 2x = 37

Reorder the terms:
1 + 8 + 3x + 2x + 2x = 37

Combine like terms: 1 + 8 = 9
9 + 3x + 2x + 2x = 37

Combine like terms: 3x + 2x = 5x
9 + 5x + 2x = 37

Combine like terms: 5x + 2x = 7x
9 + 7x = 37

Solving
9 + 7x = 37

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-9' to each side of the equation.
9 + -9 + 7x = 37 + -9

Combine like terms: 9 + -9 = 0
0 + 7x = 37 + -9
7x = 37 + -9

Combine like terms: 37 + -9 = 28
7x = 28

Divide each side by '7'.
x = 4

Simplifying
x = 4

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