3x+(2x-3)=7(x-2)-x

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Solution for 3x+(2x-3)=7(x-2)-x equation: 



3x+(2x-3)=7(x-2)-x

We move all terms to the left:

3x+(2x-3)-(7(x-2)-x)=0

We get rid of parentheses

3x+2x-(7(x-2)-x)-3=0



We calculate terms in parentheses: -(7(x-2)-x), so:

7(x-2)-x

We add all the numbers together, and all the variables

-1x+7(x-2)

We multiply parentheses

-1x+7x-14

We add all the numbers together, and all the variables

6x-14

Back to the equation:

-(6x-14)



We add all the numbers together, and all the variables

5x-(6x-14)-3=0

We get rid of parentheses

5x-6x+14-3=0

We add all the numbers together, and all the variables

-1x+11=0

We move all terms containing x to the left, all other terms to the right

-x=-11

x=-11/-1

x=+11

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