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3x+(2x-3)=7(x-2)-x+2
We move all terms to the left:
3x+(2x-3)-(7(x-2)-x+2)=0
We get rid of parentheses
3x+2x-(7(x-2)-x+2)-3=0
We calculate terms in parentheses: -(7(x-2)-x+2), so:We add all the numbers together, and all the variables
7(x-2)-x+2
We add all the numbers together, and all the variables
-1x+7(x-2)+2
We multiply parentheses
-1x+7x-14+2
We add all the numbers together, and all the variables
6x-12
Back to the equation:
-(6x-12)
5x-(6x-12)-3=0
We get rid of parentheses
5x-6x+12-3=0
We add all the numbers together, and all the variables
-1x+9=0
We move all terms containing x to the left, all other terms to the right
-x=-9
x=-9/-1
x=+9
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