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3x+(2x-5)=13-2(x+2
We move all terms to the left:
3x+(2x-5)-(13-2(x+2)=0
We get rid of parentheses
3x+2x-(13-2(x+2)-5=0
We add all the numbers together, and all the variables
5x-(13-2(x+2)-5=0
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