3x+(2x-7)4=38

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Solution for 3x+(2x-7)4=38 equation: 



3x+(2x-7)4=38

We move all terms to the left:

3x+(2x-7)4-(38)=0

We multiply parentheses

3x+8x-28-38=0

We add all the numbers together, and all the variables

11x-66=0

We move all terms containing x to the left, all other terms to the right

11x=66

x=66/11

x=6

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