3x+(3(x-1)+8)=x+19

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Solution for 3x+(3(x-1)+8)=x+19 equation:



3x+(3(x-1)+8)=x+19
We move all terms to the left:
3x+(3(x-1)+8)-(x+19)=0
We get rid of parentheses
3x+(3(x-1)+8)-x-19=0
We calculate terms in parentheses: +(3(x-1)+8), so:
3(x-1)+8
We multiply parentheses
3x-3+8
We add all the numbers together, and all the variables
3x+5
Back to the equation:
+(3x+5)
We add all the numbers together, and all the variables
2x+(3x+5)-19=0
We get rid of parentheses
2x+3x+5-19=0
We add all the numbers together, and all the variables
5x-14=0
We move all terms containing x to the left, all other terms to the right
5x=14
x=14/5
x=2+4/5

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