3x+(3-2)=10

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Solution for 3x+(3-2)=10 equation: 



3x+(3-2)=10

We move all terms to the left:

3x+(3-2)-(10)=0

determiningTheFunctionDomain
3x-10+(3-2)=0

We add all the numbers together, and all the variables

3x-10+1=0

We add all the numbers together, and all the variables

3x-9=0

We move all terms containing x to the left, all other terms to the right

3x=9

x=9/3

x=3

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