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3x+(3x-12)=x/4
We move all terms to the left:
3x+(3x-12)-(x/4)=0
We add all the numbers together, and all the variables
3x+(3x-12)-(+x/4)=0
We get rid of parentheses
3x+3x-x/4-12=0
We multiply all the terms by the denominator
3x*4+3x*4-x-12*4=0
We add all the numbers together, and all the variables
-1x+3x*4+3x*4-48=0
Wy multiply elements
-1x+12x+12x-48=0
We add all the numbers together, and all the variables
23x-48=0
We move all terms containing x to the left, all other terms to the right
23x=48
x=48/23
x=2+2/23
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