3x+(4+x)=49

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Solution for 3x+(4+x)=49 equation: 



3x+(4+x)=49

We move all terms to the left:

3x+(4+x)-(49)=0

We add all the numbers together, and all the variables

3x+(x+4)-49=0

We get rid of parentheses

3x+x+4-49=0

We add all the numbers together, and all the variables

4x-45=0

We move all terms containing x to the left, all other terms to the right

4x=45

x=45/4

x=11+1/4

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