3x+(4x+1)=13

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Solution for 3x+(4x+1)=13 equation: 



3x+(4x+1)=13

We move all terms to the left:

3x+(4x+1)-(13)=0

We get rid of parentheses

3x+4x+1-13=0

We add all the numbers together, and all the variables

7x-12=0

We move all terms containing x to the left, all other terms to the right

7x=12

x=12/7

x=1+5/7

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