3x+(4x+2)=16

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Solution for 3x+(4x+2)=16 equation: 



3x+(4x+2)=16

We move all terms to the left:

3x+(4x+2)-(16)=0

We get rid of parentheses

3x+4x+2-16=0

We add all the numbers together, and all the variables

7x-14=0

We move all terms containing x to the left, all other terms to the right

7x=14

x=14/7

x=2

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