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3x+(4x+3)=96
We move all terms to the left:
3x+(4x+3)-(96)=0
We get rid of parentheses
3x+4x+3-96=0
We add all the numbers together, and all the variables
7x-93=0
We move all terms containing x to the left, all other terms to the right
7x=93
x=93/7
x=13+2/7
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