3x+(4x+44)=79

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Solution for 3x+(4x+44)=79 equation: 



3x+(4x+44)=79

We move all terms to the left:

3x+(4x+44)-(79)=0

We get rid of parentheses

3x+4x+44-79=0

We add all the numbers together, and all the variables

7x-35=0

We move all terms containing x to the left, all other terms to the right

7x=35

x=35/7

x=5

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