3x+(4x+5)=68

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Solution for 3x+(4x+5)=68 equation: 



3x+(4x+5)=68

We move all terms to the left:

3x+(4x+5)-(68)=0

We get rid of parentheses

3x+4x+5-68=0

We add all the numbers together, and all the variables

7x-63=0

We move all terms containing x to the left, all other terms to the right

7x=63

x=63/7

x=9

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