3x+(4x-1)2=(x-4)2-3(5-x)

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Solution for 3x+(4x-1)2=(x-4)2-3(5-x) equation: 



3x+(4x-1)2=(x-4)2-3(5-x)

We move all terms to the left:

3x+(4x-1)2-((x-4)2-3(5-x))=0

We add all the numbers together, and all the variables

3x+(4x-1)2-((x-4)2-3(-1x+5))=0

We multiply parentheses

3x+8x-((x-4)2-3(-1x+5))-2=0



We calculate terms in parentheses: -((x-4)2-3(-1x+5)), so:

(x-4)2-3(-1x+5)

We multiply parentheses

2x+3x-8-15

We add all the numbers together, and all the variables

5x-23

Back to the equation:

-(5x-23)



We add all the numbers together, and all the variables

11x-(5x-23)-2=0

We get rid of parentheses

11x-5x+23-2=0

We add all the numbers together, and all the variables

6x+21=0

We move all terms containing x to the left, all other terms to the right

6x=-21

x=-21/6

x=-3+1/2

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