3x+(4x-11)=137

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Solution for 3x+(4x-11)=137 equation: 



3x+(4x-11)=137

We move all terms to the left:

3x+(4x-11)-(137)=0

We get rid of parentheses

3x+4x-11-137=0

We add all the numbers together, and all the variables

7x-148=0

We move all terms containing x to the left, all other terms to the right

7x=148

x=148/7

x=21+1/7

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