3x+(5(X+2))=2

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Solution for 3x+(5(X+2))=2 equation: 



3x+(5(x+2))=2

We move all terms to the left:

3x+(5(x+2))-(2)=0



We calculate terms in parentheses: +(5(x+2)), so:

5(x+2)

We multiply parentheses

5x+10

Back to the equation:

+(5x+10)



We get rid of parentheses

3x+5x+10-2=0

We add all the numbers together, and all the variables

8x+8=0

We move all terms containing x to the left, all other terms to the right

8x=-8

x=-8/8

x=-1

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